Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Exercises and Problems: 44

Answer

Please see the work below.

Work Step by Step

We know that the centripetal force should be equal to the force of gravity that is $mg=\frac{mv^2}{r}$ This simplifies to: $v=\sqrt{rg}$ We plug in the known values to obtain: $v=\sqrt{(0.85)(9.8)}=2.9\frac{m}{s}$
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