## Essential University Physics: Volume 1 (3rd Edition)

We know that $a=\frac{F}{m}$ We plug in the known values to obtain: $a=\frac{300000}{55000}=5.455\frac{m}{s^2}$ The required distance to stop is $x=\frac{v^2}{2a}$ We plug in the known values to obtain: $x=\frac{(36)^2}{(2)(5.455)^2}=120m$ The length of the system is 132 m and hence the plane can stop.