#### Answer

Please see the work below.

#### Work Step by Step

We know that
$a=\frac{F}{m}$
We plug in the known values to obtain:
$a=\frac{300000}{55000}=5.455\frac{m}{s^2}$
The required distance to stop is
$x=\frac{v^2}{2a}$
We plug in the known values to obtain:
$x=\frac{(36)^2}{(2)(5.455)^2}=120m$
The length of the system is 132 m and hence the plane can stop.