Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 4 - Exercises and Problems - Page 67: 33


$1.36\times 10^{14} \ N$

Work Step by Step

We first find the acceleration: $a =\frac{\Delta v}{t} =\frac{2.592\times 10^{10} \ m/s}{120 \ s}=2.16\times10^8$ We now find force using Newton's second law: $F=ma=2.16\times10^8\times(630,000)=1.36\times 10^{14} \ N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.