Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems - Page 47: 26


Please see the work below.

Work Step by Step

We know that according to parallelogram law of vector addition: $(v_2)^2=(v_1)^2+2v_1v_2cos\theta$ We plug in the known values to obtain: $(5.7)^2=(2.4)^2+(3.3)^2+2(2.4)(3.3)cos\theta$ This can be rearranged as: $cos\theta=\frac{(5.7)^2-(2.4)^2-(3.3)^2}{2\times 2.4\times 3.3}=1$ $\theta=0^{\circ}$
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