Answer
Please see the work below.
Work Step by Step
We know that according to parallelogram law of vector addition:
$(v_2)^2=(v_1)^2+2v_1v_2cos\theta$
We plug in the known values to obtain:
$(5.7)^2=(2.4)^2+(3.3)^2+2(2.4)(3.3)cos\theta$
This can be rearranged as:
$cos\theta=\frac{(5.7)^2-(2.4)^2-(3.3)^2}{2\times 2.4\times 3.3}=1$
$\theta=0^{\circ}$
