Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 2 - Exercises and Problems: 51

Answer

Please see the work below.

Work Step by Step

We know that $\Delta d=142-23=119m$ Now $a=\frac{v^2-v_{\circ}^2}{2\Delta d}$ $a=\frac{(0.75)^2-(32)^2}{2.119}=4.3\frac{m}{s^2}$
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