Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 2 - Exercises and Problems: 13

Answer

a) 375 $\frac{yard}{min}$ b) 5.72 $min$

Work Step by Step

a) The average velocity is defined as the change in displacement over the change in time: $\bar{v} = \frac{\Delta d}{\Delta t}$ $\Delta d =$ 26 miles $+$ 385 yards = 46135 yards $\Delta t =$ 2 hours $+$ 3 min = 123 min $\bar{v} = \frac{\Delta d}{\Delta t} = \frac{46135}{123} =$ 375$\frac{yard}{min}$ b) $d =$ 25 miles = 44000 yards $v = $ 375$\frac{yard}{min}$ $t = \frac{d}{v} =$ 117.8 min The extra time is 123 - 117.26 = 5.72 minutes
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