#### Answer

12.1 KJ/K

#### Work Step by Step

We know that the entropy of vaporization of water is $109.2\frac{J}{molK}$, and we know that 2 kg of water is 111 moles. Thus, we find:
$\Delta S = 111.05 \times 109.02 \approx 12.1 KJ/K $

Published by
Pearson

ISBN 10:
0321993721

ISBN 13:
978-0-32199-372-4

12.1 KJ/K

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