Answer
Yes
Work Step by Step
We know that the thermal waste power is equal to:
$P_{waste}=670-360=310$
We know that the efficiency is:
$P_{eff}=\frac{360}{670}=.537 = \fbox{53.7 percent}$
Thus, both requirements are met.
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 18 - Exercises and Problems - Page 333: 77
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