Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 17 - Section 17.3 - Thermal Expansion - Example - Page 311: 17.5


.274 Liters are lost.

Work Step by Step

We find the change in volume of the can and the gas to find: $\Delta V_{can}=\beta V\Delta T=(3)(12\times10^{-6})(20)(15)=.0108L$ $\Delta V_{gas}=\beta V\Delta T=(95\times10^{-5})(20)(15)=.285L$ Thus, .274 Liters are lost.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.