Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 17 - Section 17.2 - Phase Changes - Example: 17.3

Answer

542 seconds

Work Step by Step

We first find the value of Q: $Q = L_fm = (259)(2.5 \times10^5)=65GJ$ We use this to find the change in time: $\Delta T=(65GJ)(.12 \ GJ/s)=542\ s$
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