Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 17 - Exercises and Problems - Page 315: 76


The proof is below.

Work Step by Step

We use the power that the exponential is raised to in order to find: $1 = |\frac{-mv^2}{2kT}|$ $1 = |\frac{mv^2}{2kT}|$ $v = \sqrt{\frac{2kT}{m}}$
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