Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Section 16.4 - Thermal-Energy Balance - Example: 16.6

Answer

$21^{\circ}C $

Work Step by Step

We use the equation for H to find: $H = (120 \ W/^{\circ}C)(\Delta T)$ $\Delta T = \frac{H}{120 \ W/^{\circ}C} $ $\Delta T = \frac{2.5 \times 10^3 \ W}{120 \ W/^{\circ}C} = 21^{\circ}C $
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