#### Answer

$-3 \ MW$

#### Work Step by Step

We use the known equation for H to obtain:
$H = \frac{-kA \Delta T}{\Delta x}$
$H = \frac{-(.61)(1.5\times 10^6)(26)}{8}\approx 3 \ MW$

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Published by
Pearson

ISBN 10:
0321993721

ISBN 13:
978-0-32199-372-4

$-3 \ MW$

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