#### Answer

4000 seconds

#### Work Step by Step

We first find the value of Q:
$Q = mc \Delta t = (150)(4184)(50-18) \approx 20 \ MJ$
We now find the change in time:
$\Delta t = \frac{20 \times 10^6 \ J }{5 \times 10^3 \ J/S} = 4000 \ s$

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Published by
Pearson

ISBN 10:
0321993721

ISBN 13:
978-0-32199-372-4

4000 seconds

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