Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Exercises and Problems - Page 302: 80


The proof is below.

Work Step by Step

We start with the given equation: $ H = -kA \frac{dT}{dr}$ We know that the area of the sides is $\pi R^2$, so we find: $ \frac{H}{\pi R_1^2-\pi R_2^2} dr = -kLdT $ Applying the integral on both sides, it follows: $H = \frac{\pi kR_1R_2(T_1-T_2)}{(L)}$
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