Answer
a) 10 meters
b) 110 MPa
Work Step by Step
a) We use the equation for the depth to find:
$ h = \frac{p-p_0}{\rho g}= \frac{2.02\times 10^5 - 1.01\times 10^5}{1030\times 9.81}= 10 \ m$
b) We can now find the pressure:
$= \frac{100}{10} \times 11 \times 10^ 3 = 110 \ MPa$
