Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 15 - Exercises and Problems - Page 282: 79


The answer is below.

Work Step by Step

We know that the maximum load is equal to quantity of the difference between the cross sectional area of the ship and that of the triangle with height $h_0$ multiplied by the length of the ship, L, and the density of water, $\rho$. Thus, we find: $ A = h^2 tan \theta$ This means: $m = \rho L (h_0^2 - h_1^2)tan \frac{\theta}{2}$
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