Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

Chapter 15 - Exercises and Problems - Page 281: 65

Answer

$14.6 \ kg$

Work Step by Step

We find the following equation for the mass it can support: $m = \frac{\mu P\pi d^2}{4g}$ Plugging in the known values, we obtain: $m = \frac{(.72)(1.01\times10^5)(\pi)(.05)^2}{4(9.81)}=14.6 \ kg$

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