Answer
$14.6 \ kg$
Work Step by Step
We find the following equation for the mass it can support:
$ m = \frac{\mu P\pi d^2}{4g}$
Plugging in the known values, we obtain:
$ m = \frac{(.72)(1.01\times10^5)(\pi)(.05)^2}{4(9.81)}=14.6 \ kg$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 15 - Exercises and Problems - Page 281: 65
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