Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 15 - Exercises and Problems - Page 279: 28


.93 meters

Work Step by Step

We use the known equation to obtain: $ h = \frac{p-p_{atm}}{\rho g} = \frac{(1)(101.3\times 10^3)-(.91)(101.3\times10^3)}{1000\times9.81}=.93\ m$
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