Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 15 - Exercises and Problems: 20

Answer

Please see the work below.

Work Step by Step

We can find the weight as $W=PA$ We plug in the known values to obtain: $W=(1.01\times 10^5Pa)(1m^2)$ $P=1.01\times 10^5N$
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