## Essential University Physics: Volume 1 (3rd Edition)

We first must find the wavelength: $\lambda=\frac{v}{f}=\frac{330}{22}=15\ m$ a) Since the pipe is closed at an end, the fundamental frequency requires a length 1/4 of the length of the pipe, which is: $15 \times \frac{1}{4}=3.75\ m$ b) Since the pipe is open at both ends, the fundamental frequency requires a length 1/2 of the length of the pipe, which is: $15 \times \frac{1}{2}=7.5\ m$