# Chapter 14 - Exercises and Problems: 68

a) 3.75 meters b) 7.5 meters

#### Work Step by Step

We first must find the wavelength: $\lambda=\frac{v}{f}=\frac{330}{22}=15\ m$ a) Since the pipe is closed at an end, the fundamental frequency requires a length 1/4 of the length of the pipe, which is: $15 \times \frac{1}{4}=3.75\ m$ b) Since the pipe is open at both ends, the fundamental frequency requires a length 1/2 of the length of the pipe, which is: $15 \times \frac{1}{2}=7.5\ m$

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