## Essential University Physics: Volume 1 (3rd Edition)

We first find the time: $t = \frac{2m}{b}ln2= \frac{2\times 1200}{230}ln2= 7.23 s$ We now find the period: $T = 2\pi \sqrt{\frac{m}{k}}= 2\pi \sqrt{\frac{1200}{58 \times10^3 }}= .904s$ Thus: $=\frac{7.23s}{.904s}\approx \fbox{8}$