## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 13 - Section 13.5 - Energy in Simple Harmonic - Example - Page 233: 13.5

#### Answer

$v = \frac{\omega A}{\sqrt{2}}$

#### Work Step by Step

We find: $\frac{1}{2}mv^2 = \frac{1}{2}(\frac{1}{2}m\omega^2A^2)$ $\frac{1}{2}mv^2 =(\frac{1}{4}m\omega^2A^2)$ $v = \frac{\omega A}{\sqrt{2}}$

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