#### Answer

The chair was defective.

#### Work Step by Step

We know that the net torques are 0. Thus, we find:
$(.38)(F_{T1})=-.16F_{T2}$
We now use the fact that the net force is 0:
$(12)(9.81)+F_{T2}=F_{T1}$
Substitution gives:
$(.38)(F_{T2}+117.72)=.16F_{T2}$
$F_{T2}=82.84\ N$
Thus, the chair was defective.