## Essential University Physics: Volume 1 (3rd Edition)

We know that the net torques are 0. Thus, we find: $(.38)(F_{T1})=-.16F_{T2}$ We now use the fact that the net force is 0: $(12)(9.81)+F_{T2}=F_{T1}$ Substitution gives: $(.38)(F_{T2}+117.72)=.16F_{T2}$ $F_{T2}=82.84\ N$ Thus, the chair was defective.