#### Answer

Please see the work below.

#### Work Step by Step

We know that moment of inertia is given as
$I=mr^2$
We plug in the known values to obtain:
$I=(0.640)(\frac{0.90}{2})^2=0.1296Kgm^2$
Then angular speed is given as
$\omega=2\pi(\frac{170}{60})=17.80\frac{rad}{s}$
Thus, the angular momentum is given as
$L=I\omega$
We plug in the known values to obtain:
$L=(0.1296)(17.80)=2.3kg\frac{m^2}{s}$