## Essential University Physics: Volume 1 (3rd Edition)

a) We use Newton's Second Law to find: $T = mg - ma = (50)(9.81-3.7)=305.5 \ N$ b) We use the equation for torque to find rotational inertia: $I =\frac{\tau}{\alpha} \\ I= \frac{Fr}{\frac{a}{r}}$ $\frac{1}{2}mr^2 =\frac{Fr^2}{a}\\ m = \frac{2F}{a}=\frac{2\times 305.5}{3.7}=165.135\ kg$