Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 10 - Exercises and Problems - Page 186: 66


a) 305.5 N b) 165 kilograms

Work Step by Step

a) We use Newton's Second Law to find: $T = mg - ma = (50)(9.81-3.7)=305.5 \ N$ b) We use the equation for torque to find rotational inertia: $I =\frac{\tau}{\alpha} \\ I= \frac{Fr}{\frac{a}{r}}$ $\frac{1}{2}mr^2 =\frac{Fr^2}{a}\\ m = \frac{2F}{a}=\frac{2\times 305.5}{3.7}=165.135\ kg$
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