Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 1 - Exercises and Problems: 67

Answer

Please see the work below.

Work Step by Step

We can find the volume of a cell as follows $V_{cell}=\frac{4}{3}\pi(R_{cell})^3$ $V_{cell}=\frac{4}{3}\pi(\frac{D_{cell}}{2})^3$ We plug in the known values to obtain: $V_{cell}=\frac{4}{3}\pi(\frac{10\times 10^{-6}}{2})^3$ $V_{cell}=5.24\times 10^{-16}m^3$
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