## Essential University Physics: Volume 1 (3rd Edition)

We can find the volume of a cell as follows $V_{cell}=\frac{4}{3}\pi(R_{cell})^3$ $V_{cell}=\frac{4}{3}\pi(\frac{D_{cell}}{2})^3$ We plug in the known values to obtain: $V_{cell}=\frac{4}{3}\pi(\frac{10\times 10^{-6}}{2})^3$ $V_{cell}=5.24\times 10^{-16}m^3$