Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 26 - Think and Solve - Page 501: 35


500 s, which is about 8.3 min. 1000 s, which is less than Ole Roemer's determination of 1300 s.

Work Step by Step

If c denotes the speed of light, then $d = 1.5 \times 10^{11} m = ct$. Solve for t = d/c. $$\frac{1.5 \times 10^{11} m }{300,000,000 m/s} = 500 s$$ The time for light to cross the diameter of the Earth’s orbit is twice that number, or 1000 s. Ole Roemer got reasonably close (question 33).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.