Answer
$\Delta T = 17.8^{\circ}C$.
Work Step by Step
Calculate the work that the hammer does on the nail.
$$F \times d = (600 N)(0.08 m) = 48 J$$
This energy input raises the temperature of the nail, and the change can be found from $Q = cm\Delta T$.
$$48 J = (450 J/(kg^{\circ} C))(0.006 kg)(\Delta T)$$
Solve to get $\Delta T = 17.8^{\circ}C$.
