## Conceptual Physics (12th Edition)

Published by Addison-Wesley

# Chapter 17 - Think and Solve: 43

#### Answer

$$\Delta T = 1.1^{\circ}C$$

#### Work Step by Step

Using the hint in the problem, we set half the initial potential energy equal to the energy needed to raise the temperature of that mass of iron. Notice that the mass cancels out. $$\frac{1}{2}mgh = cm \Delta T$$ $$\Delta T = \frac{1}{2c}gh$$ $$\Delta T = \frac{1}{2 (450 J/kg ^{\circ}C)} (9.8 \frac{m}{s^{2}}) (100 m)$$ $$\Delta T = 1.1^{\circ}C$$

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