Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 15 - Plug and Chug - Page 298: 34


The book asks us to show that 12570 J are required to raise the temperature of 0.30 kg of water from $22^{\circ}C$ to $30^{\circ}C$ . There is a typo; the answer is actually 10056 J.

Work Step by Step

$$Q = cm \Delta T$$ $$=\frac{4190 J}{kg \cdot ^{\circ}C}(0.30 kg)(30^{\circ}C - 22^{\circ}C ) = 10056 J$$
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