Answer
The book asks us to show that 12570 J are required to raise the temperature of 0.30 kg of water from $22^{\circ}C$ to $30^{\circ}C$ . There is a typo; the answer is actually 10056 J.
Work Step by Step
$$Q = cm \Delta T$$
$$=\frac{4190 J}{kg \cdot ^{\circ}C}(0.30 kg)(30^{\circ}C - 22^{\circ}C ) = 10056 J$$
