College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 9 - Solids and Fluids - Learning Path Questions and Exercises - Exercises - Page 350: 21

Answer

a) $9.8\times10^{4} Pa$ b) $2.0\times10^{5} Pa$

Work Step by Step

a) P= $\rho g h= 1000\,kg m^{-3}\times9.8\,ms^{-2}\times10\,m$ $=9.8\times10^{4} Pa$ b) $P= P_{a}+ \rho g h$$= 1.013\times10^{5}\,Pa+9.8\times10^{4} Pa$ $\approx2.0\times10^{5} Pa$
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