Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 303: 4

Speed of center of mass = 3.6m/s Total angle rotated = No of revolutions $\times$ 2pi= 7.5$\times$ 2pi = 15pi radians. Time taken = 2 secs So, angular velocity = $\frac{\theta}{t}=\frac{15pi}{2}=3.6m/s$ Since , $v=\omega r=3.6m/s $ the ball is rolling without slippage.

Speed of center of mass = 3.6m/s Total angle rotated = No of revolutions $\times$ 2pi= 7.5$\times$ 2pi = 15pi radians. Time taken = 2 secs So, angular velocity = $\frac{\theta}{t}=\frac{15pi}{2}=3.6m/s$ Since , $v=\omega r=3.6m/s $ the ball is rolling without slippage.