Answer
$0.0011rad/s^{2}$
Work Step by Step
$\omega^{2}=\omega_{0}^{2}+2a\Delta\theta$
Initial angular velocity = 0,
So, $angular\,\, acceleration =a = \frac{0.26^{2}}{2\times 31.4}=0.0011rad/s^{2}$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 262: 45
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