## College Physics (7th Edition)

Work done by the 1-hp motor, $W_1=P_1\times t_1=t_1$.\\ Work done by the 2-hp motor, $W_2=P_2\times t_2=2t_2$.\\ Taking the ratio of the work done in the two cases, \begin{align*} W_1=\frac{t_1}{2t_2}W_2 \end{align*}For, the same amount of time i.e. $t_1=t_2$, $W_1=0.5\times W_2$