College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 5 - Work and Energy - Learning Path Questions and Exercises - Exercises - Page 176: 44


a). $0.154J$ b). $0.3087J$

Work Step by Step

a). $mgsin30^{\circ}=k\Delta x$ $\Delta x=\frac{mgsin30^{\circ}}{k}=\frac{1.5\times9.8\times0.5}{175}=0.042m$ Change in elastic potential energy of system = $\frac{1}{2}k(\Delta x)^{2}=0.154J$ b). System's change in potential energy =$mg\Delta xsin30^{\circ}$ $=1.5\times9.8\times0.042\times0.5=0.3087J$
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