## College Physics (7th Edition)

a) The net force acting on 2.0 kg ball: F=mg= $2.0\,kg\times9.8m/s^{2}=20.\,N$ On 6.0 kg ball: F= $6.0kg\times9.8m/s^{2}=59\,N$ b) a in free fall is same for both equal to $9.8 m/s^{2}$