Answer
$p+v_{e}=n+beta^{+}$ and $p+n=H^{2}_{1}+gamma$
The gamma ray is from the formation of deuterium.
The two 0.511 MeV gamma rays result from the pair annihilation when the positron meets an electron.
Work Step by Step
$p+v_{e}=n+beta^{+}$ and $p+n=H^{2}_{1}+gamma$
The gamma ray is from the formation of deuterium.
The two 0.511 MeV gamma rays result from the pair annihilation when the positron meets an electron.
