College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Conceptual Questions - Page 95: 10


The launch angle of the golf ball was $45^{\circ}$.

Work Step by Step

For a ball launched moving up at an angle $\theta$ to the horizontal, it also lands moving down at an angle $\theta$ to the horizontal (in Figure 3.11). The rotation of the velocity vector is thus given by the sum of the two angles above - $2\theta=90^{\circ}$. Therefore, the launch angle, $\theta$ of the golf ball was $45^{\circ}$.
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