College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 28 - Quantum Mechanics and Atomic Physics - Learning Path Questions and Exercises - Exercises - Page 962: 4


0.1227 nm

Work Step by Step

Wavelength of the electron, λ= $\frac{1.227}{\sqrt V}$nm Given that V= 100 V Therefore, λ= $\frac{1.227}{\sqrt 100}nm$= 0.1227 nm
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