Answer
(d) one can be larger or smaller than the other, depending on the object's velocity.
Work Step by Step
The magnitude of the relativistic momentum of a particle of mass m moving with speed v is :-
$p=\frac{mV}{\sqrt (1-\frac{V^{2}}{c^{2}})}=vmV$
where $mV$ is the Newtonian momentum and $v=\frac{1}{\sqrt (1-\frac{V^{2}}{c^{2}})}$
When $V<1$
So the magnitude of relativistic momentum is larger than the Newtonian momentum at high speeds. (d) is the answer.
