College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 25 - Vision and Optical Instruments - Learning Path Questions and Exercises - Exercises - Page 873: 51

Answer

a). (3) blue b). $\theta_{min}=0.004^{\circ}$ for 400-nm light and $\theta_{min}=0.007^{\circ}$ for 700-nm light.

Work Step by Step

a). (3) For blue color the human eye can see the finest details because as per the minimum angle of resolution equation : $\theta_{min}=\frac{1.22\times wavelength}{D}$ D is fixed as pupil of human eye has nearly same diameter. Hence more is the wavelength more will be the value of $\theta_{min}$ and less fine will be the details that can be observed by human eye. b). $\theta_{min}=\frac{1.22\times wavelength}{D}$ for wavelength, $lambda_{1}$: $\theta_{min}=\frac{1.22\times wavelength}{D}=\frac{1.22\times400\times10^{-9}}{7\times 10^{-3}}=0.004^{\circ}$ for wavelength, $lambda_{2}$: $\theta_{min}=\frac{1.22\times wavelength}{D}=\frac{1.22\times700\times10^{-9}}{7\times 10^{-3}}=0.007^{\circ}$
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