Chapter 25 - Vision and Optical Instruments - Learning Path Questions and Exercises - Exercises - Page 872: 19

a). $0.17^{\circ}$ b). $0.082^{\circ}$

a). Car height = 1.5m the car is viewed from 500m. so $tan\theta=\frac{object\,\,height}{distance \,\,of\,\,observer}=\frac{1.5}{500}=0.003$ $tan\theta\approx\theta=0.003 radians=0.17^{\circ}$ b). when viewed from 1050m. $tan\theta=\frac{object\,\,height}{distance \,\,of\,\,observer}=\frac{1.5}{1050}=0.0014$ $tan\theta\approx\theta=0.0014 radians=0.082^{\circ}$