Answer
$11 cm$
Work Step by Step
By Snell's Law,
$n_{a}\times sin50^{\circ}=n_{w}\times sin\theta_{r}$
or, $sin\theta_{r}=\frac{sin50^{\circ}}{1.33}=0.5759$
or, $\theta_{r}=35.17^{\circ}$
If the coin is at a distance x from the side of the container,
then $x= tan35.17^{\circ} \times 15 cm=11cm$