College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 22 - Reflection and Refraction of Light - Learning Path Questions and Exercises - Exercises - Page 774: 18

Answer

$33.3^{\circ}$

Work Step by Step

Let the critical angle be $\theta_{c}$. So, $\theta_{c}=sin^{-1}\frac{n_{2}}{n_{1}}=sin^{-1}\frac{1.33}{2.42}$, by inserting the values of indexes of refraction for diamond and water. $\theta_{c}=sin^{-1}0.5495=33.3^{\circ}$
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