College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 21 - AC Circuits - Learning Path Questions and Exercises - Exercises - Page 749: 17

Answer

$1.3\times10^{3}Ohm$

Work Step by Step

Capacitive reactance = $X_{c}=\frac{1}{2\times pi\times f\times C}$ $f=60Hz, C=2.0 micro-farad$ So, $X_{c}=\frac{1}{2\times pi \times 60\times 2\times10^{-6}}=1326 Ohm\approx1.3\times10^{3}Ohm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.