## College Physics (7th Edition)

a) $10A$ b) $14.1A$ c) $12Ohm$
a) Average power = $1200 W$ , RMS voltage =$120V$ RMS current = $\frac{RMS\,\, power }{RMS\,\, voltage}=\frac{1200}{120}=10A$ b) Peak current = $\sqrt 2\times 10A=14.1A$ c) Resistance = $\frac{RMS \,\,voltage}{RMS\,\, current}=\frac{120}{10}=12Ohm$