Answer
a). $a=-1.78m/s^{2}$
b). $t=6.275s$
Work Step by Step
a). $25mi/hr = 25\times \frac{1609 m}{3600 s}=11.17m/s$
$v^{2}=u^{2}+2aS$
$0=11.17^{2}+70a$
i.e. $a=-1.78m/s^{2}$
b). $v=u+at$
$0=11.17-1.78\times t$
$t=6.275s$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 62: 39
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