College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 19 - Magnetism - Learning Path Questions and Exercises - Multiple Choice Questions - Page 687: 9


(d) both (a) and (c) are possible

Work Step by Step

The magnitude of magnetic field on a charged particle with charge q and speed v is $F=qvBsin\theta$, where $\theta$ is the angle between velocity of the particle and magnetic field B. In this case, $v\ne0$, $B\ne0$, thus for F=0, we must have $\theta=0^{\circ}$ or $\theta=180^{\circ}$. Therefore the magnetic field could be in the same or opposite direction .
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