## College Physics (7th Edition)

Magnetic force, $\vec{F}=q (\vec{V} \times \vec{B})$ Magnitude of centripetal force $\frac{mV^2}{r}$ Magnitude of Linear momentum $p= mv$ Kinetic energy $K=\frac{1}{2}mV^2$
Magnetic force $\vec{F}=q (\vec{V} \times \vec{B})$ Magnitude = F=qVB Now, centripetal force $\frac{mV^2}{r}= qVB$ Therefore $mV= qBr=P$ (This is magnitude of linear momentum, P) From here we can get the radius as well $r=\frac{mV}{qB}$ Kinetic energy, $K=\frac{1}{2}mV^2=\frac{m^2V^2}{2m}=\frac{P^2}{2m}$ We get the answers by putting the known values(please see the documents attached)